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8. Jenny is getting dressed for school,
• She has 2 pairs of black pants, 1 pair of brown pants, and 2 pairs of blue pants in her
closet
. She also has 2 pink T-shirts and blue T-shirts in her closet.
• Without looking, Jonny pulls out one pair of pants and one T-shirt from her closet.
What is the probability that Jenny pulls out a pair of black pants and a blue T-shirt?

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Answer:

[tex]\huge\boxed{\bf\: Probability = \frac{4}{9}}[/tex]

Step-by-step explanation:

According to the given information,

  • Pairs of black pants = 2
  • Pair of brown pants = 1
  • Pairs of blue pants = 2

Then, total pairs of pants = 2 + 1 + 2 = 5

Similarly,

  • Pink T-shirts = 2
  • Blue T-shirts = 2

Then, total number of T-shirts = 4

This gives us the total nunber of clothing articles with Jenny, i.e.,

Total pairs of pants + Total number of T-shirts

= 5 + 4

= 9

Now, the probability of pulling out a pair of black pants & a blue T-shirt will be:

Total pairs of black pants + Total nunber of blue T-shirts/Total clothing articles

= 2 + 2 / 9

= 4/9

[tex]\rule{150}{2}[/tex]

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