contestada

If O is an angle in standard position and its terminal side passes through the point
(8,-7), find the exact value of csc 0 in simplest radical form.

Respuesta :

Step-by-step explanation:

Let first find the x and y xomponets.

X componets is 8 and the y componets is -7 so

[tex]r = \sqrt{ {x}^{2} + {y}^{2} } [/tex]

[tex]r = \sqrt{ 64 + 49} [/tex]

[tex]r = \sqrt{113} [/tex]

[tex] \csc(x) = \frac{r}{y} [/tex]

So

[tex] \csc(x) = - \frac{ \sqrt{113} }{ 7} [/tex]

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