Write an equation of the line in slope- intercept form
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Answer:
[tex]d)\ y=x+5[/tex]
Step-by-step explanation:
Slope (m) form: [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]m=\frac{y_2-y_1}{x_2-x_1} \\\\m=\frac{5-2}{0-(-3)} \\\\m=\frac{3}{(0+3)} \\\\m=\frac{3}{3} \\\\m=1[/tex]
[tex]y=mx+b\\y=1x+b\\y=x+b[/tex]
(0, 5)
[tex]5=0+b\\5=b[/tex]
[tex]y=x+5[/tex]
Check your answer:
[tex]y=x+b\\5=0+5\\5=5[/tex]
This statement is true
Hope this helps!
Answer:
D. y=x+5
Step-by-step explanation:
Find the slope of the line. Remember to use equation: m=y2−y1/x2−x1
m= 5-(2)/0-(-3)
Simplify both numerator and denominator, then divide. You'll get m=1
Use the slope 1 and a given point (−3,2) to substitute for x1 and y1 in the point-slope form y−y1=m(x−x1).
y−(2)=1⋅(x−(−3))
Simplify the equation.
y−2=1⋅(x+3)
Solve for y by multiplying x+3 by 1.
y−2=x+3
Move everything that doesnt contain y to the right by adding 2 to both sides of the equation
y=x+3+2
and then added 3 and 2.
y=x+5