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Question 7 of 10
What is the solution to this equation?
3(4x+3) = 2x - 5(3 - x) + 2
4
O A. x=-
15
10
O B. x=-22
O
5
O x-
O c. x - 22
15
O x
O D. x = -1
5

Question 7 of 10 What is the solution to this equation 34x3 2x 53 x 2 4 O A x 15 10 O B x22 O 5 O x O c x 22 15 O x O D x 1 5 class=

Respuesta :

Answer:

  • Option B

Step-by-step explanation:

Given Equation :

[tex] \qquad \sf \dashrightarrow \: 3(4x+3) = 2x - 5(3 - x) + 2[/tex]

Using distribute property:

[tex]\qquad \sf \dashrightarrow \: 12x + 9 = 2x - 15 + 5x + 2[/tex]

Adding the like terms we get :

[tex]\qquad \sf \dashrightarrow \: 12x + 9 = 2x + 5x - 15 + 2[/tex]

[tex]\qquad \sf \dashrightarrow \: 12x + 9 = 7x - 13[/tex]

Transposing the variables on the right side and constant terms on the left side :

[tex]\qquad \sf \dashrightarrow \: 12x - 7x = - 13 - 9[/tex]

[tex]\qquad \sf \dashrightarrow \: 5x = - 22[/tex]

Dividing both sides by 5 :

[tex]\qquad \sf \dashrightarrow \: \dfrac{5x}{5} = \dfrac{ - 22}{5} [/tex]

[tex]\qquad \bf \dashrightarrow \: x = \dfrac{ - 22}{5} [/tex]