Given that the length of the table is twice the width which is 1.25 m. and
the difference in the parallel side is 1 m., the area of the table is 2.5 m².
How can the area of the table be calculated?
The possible table dimensions are;
Width of the table = 1.25 m
Width of the table = The height of the trapezoid
The difference in length between the parallel sides = 2 × 0.5 m = 1 m
Longest side of the table is a parallel side of the trapezoid
Given;
Length of the longest side of the table = 2 × The width
Which gives;
Length of the longest side of the table = 2 × 1.25 m = 2.5 m
Length of other parallel side = 2.5 m - 1 m = 1.5 m
[tex]Area \ of \ a \ trapezoid = \mathbf{\dfrac{Sum \ of \ length \ of \ parallel \ sides}{2} \times Height}[/tex]
Which gives;
[tex]\mathbf{Area \ of}\ the \ \mathbf{table} = \dfrac{2.5 + 1.5}{2} \times 1.25 = 2.5[/tex]
The area of the = 2.5 m²
Learn more about the properties of a trapezoid here:
https://brainly.com/question/4758162
