The amount of Columbian's coffee is 0.25 pounds and Kona's coffee 4.75 pounds.
Data;
Let the value of Columbian coffee be represented by x
Let the value of Kona coffee be represented by y
To solve this problems, we need to write a system of equations of this problem.
[tex]4.40x+7.60y = 37.20..equation(i)\\x+y = 5...equation(ii)\\[/tex]
From equation (ii), let's make x the subject of formula
[tex]x+y =5\\x = 5 - y...equation(iii)[/tex]
Substitute equation(iii) into equation(i)
[tex]4.40x+7.60y=37.20\\x =5 - y\\4.40(5-y) + 7.60y = 37.20\\22 - 4.40y + 7.60y = 37.20\\22 + 3.20y = 37.20\\3.20y = 37.20-22\\3.20y = 15.2\\\frac{3.20y}{3.20} =\frac{15.2}{3.20}\\ y = 4.75[/tex]
Let's substitute this value into equation(ii)
[tex]x+y=5\\y = 4.75\\x+4.75=5\\x = 5 - 4.75\\x = 0.25[/tex]
From the calculations above, the amount of Columbian's coffee is 0.25 pounds and Kona's coffee 4.75 pounds.
Learn more on system of equations here;
https://brainly.com/question/14323743