contestada

You have a solution which is 45.6% by mass isopropyl alcohol (MM = 60.11 g/mol) in water. The density of this solution is 0.905 g/mL.

What is the molality of the isopropyl alcohol in the solution?

Respuesta :

Eduard22sly

The molality of the isopropyl alcohol in the solution is 13.95 m

Assumption

  • Let the mass of the solution be 100 g.
  • 45.6% by mass isopropyl alcohol = 45.6 g
  • Mass of solvent = 100 – 45.6 = 54.4 g

Determination of the mole

  • Mass of isopropyl alcohol = 45.6 g
  • Molar mass of isopropyl alcohol = 60.11 g/mol
  • Mole of isopropyl alcohol =?

Mole = mass / molar mass

Mole of isopropyl alcohol = 45.6 / 60.11

Mole of isopropyl alcohol = 0.759 mole

How to determine molality

  • Mole of isopropyl alcohol = 0.759 mole
  • Mass of solvent = 54.4 g = 54.4 / 1000 = 0.0544 Kg
  • Molality =?

Molality = mole / mass of solvent

Molality = 0.759 / 0.0544

Molality = 13.95 m

Learn more about Molality:

https://brainly.com/question/4251997

Otras preguntas