Respuesta :
Answer:
Explanation: Vi = 18k/hr = 18 x 1000/3600 = 5/s
Vf = 54k/hr = 54 x 1000/3600 = 15/s
S = 5
a = ?
t = ?
BY USING NEWTON 3RD EQUATION OF MOTION
2aS= Vf^2-Vi^2
a = Vf^2 - Vi^2/2S
a = 15^2 - 5^2/2(5)
a = 20
BY USING NEWTON 1st EQUATION OF MOTION
Vf = Vi + at
t = Vf-Vi/a
t = 15-5/20
t = 10/20 = 1/2 sec = 0.5 sec
The acceleration of the car is 20 m/s²
What is acceleration?
This is the rate of change of velocity. To calculate the acceleration of the car, we use the formula below.
Formula:
- v² = u²+2as................... Equation 1
Where:
- v = final velocity
- u = initial velocity
- a = acceleration of the car
- s = distance traveled .
Make a the subject of the equation
- a = (v²-u²)/2s............. Equation 2
From the question,
Given:
- u = 18 km/h = (18×1000/3600) = 5 m/s
- v = 54 km/h = (54×1000/3600) = 15 m/s
- s = 5 m
Substitute these values above into equation 2
- a = (15²-5²)/(2×5)
- a = (225-25)/10
- a = 200/10
- a = 20 m/s²
Hence, The acceleration of the car is 20 m/s².
Learn more about acceleration here: https://brainly.com/question/460763