A car travels with a velocity of 18km/hr, then it accelerates uniformly and travels a distance of 5m. If the velocity reached is 54 km/hr, find the acceleration and the time taken to travel this distance.​

Respuesta :

Answer:

Explanation: Vi = 18k/hr   =  18 x 1000/3600  = 5/s

                      Vf = 54k/hr  =   54 x 1000/3600 = 15/s

                       S  =  5

                        a =   ?

                        t  =   ?

           BY USING NEWTON 3RD EQUATION OF MOTION

                        2aS= Vf^2-Vi^2

                           a =  Vf^2 - Vi^2/2S

                           a =   15^2 - 5^2/2(5)

                           a  =    20

           BY USING NEWTON  1st  EQUATION OF MOTION

                          Vf = Vi + at

                            t  =  Vf-Vi/a

                            t  =  15-5/20

                            t  =  10/20 = 1/2 sec = 0.5 sec

The acceleration of the car is 20 m/s²

What is acceleration?

This is the rate of change of velocity. To calculate the acceleration of the car, we use the formula below.

Formula:

  • v² = u²+2as................... Equation 1

Where:

  • v = final velocity
  • u = initial velocity
  • a = acceleration of the car
  • s = distance traveled .

Make a the subject of the equation

  • a = (v²-u²)/2s............. Equation 2

From the question,

Given:

  • u = 18 km/h = (18×1000/3600) = 5 m/s
  • v = 54 km/h = (54×1000/3600) = 15 m/s
  • s = 5 m

Substitute these values above into equation 2

  • a = (15²-5²)/(2×5)
  • a = (225-25)/10
  • a = 200/10
  • a = 20 m/s²

Hence, The acceleration of the car is 20 m/s².

Learn more about acceleration here: https://brainly.com/question/460763