contestada

So my last question was to explain (4^7/5^2)^3 • and I got that one right but now I have this question and I’m not sure how to do it because on my last one I have to multiply the inside exponent by the outside one, except now there is not outside one

Sorry if that was confusing, but can somebody explain this to me too?

So my last question was to explain 47523 and I got that one right but now I have this question and Im not sure how to do it because on my last one I have to mul class=

Respuesta :

semsee45

Answer:

[tex]\dfrac{11^{-4}}{11^8}=\dfrac{1}{11^{12}}[/tex]

Step-by-step explanation:

Apply exponent rule:   [tex]a^{-b}=\dfrac{1}{a^b}[/tex]

[tex]11^{-4}=\dfrac{1}{11^4}[/tex]

[tex]\implies \dfrac{11^{-4}}{11^8}=\dfrac{1}{11^8 \cdot 11^4}[/tex]

Apply exponent rule:  [tex]a^b \cdot a^c=a^{b+c}[/tex]

[tex]\implies \dfrac{1}{11^8 \cdot 11^4}=\dfrac{1}{11^{(8+4)}}[/tex]

[tex]\implies \dfrac{1}{11^{(8+4)}}= \dfrac{1}{11^{12}}[/tex]

Otras preguntas