As the question depicts the trail is 10Km long but the end of the trail is 300m north from the beginning, Here the average velocity comes out to be 100m/hr.
Velocity is defined as the displacement covered by an object or a body in unit time interval.
From the problem, it is clear that the distance is 10Km but the displacement comes out to be 300m.
The time from 2:00 pm to 5:00 pm is a total of 3hours.
Now, the velocity is determined from the following formula
[tex]V=\dfrac{d}{t}[/tex]
here,
d= displacement
t= time
So, by putting values in above formula we get,
[tex]V=\dfrac{300 m}{3 hrs}[/tex]
[tex]V=100m/hr[/tex]
So, the average velocity of Sofia is 100m/hr
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