Two system of equation has the same solution as first equation of System B is obtained by adding, first equation of System A, 2 times second equation of System A.
A system of equation is the set of equation in which the finite set of equation is present for which the common solution is sought.
The equation of system A given in the problem are,
[tex]3x+2y=3[/tex]
[tex]-2x-8y=-1[/tex]
The equation of system B given in the problem are,
[tex]-x-14y=1[/tex]
[tex]-2x-8y=-1[/tex]
On solving the first equation of system A, we get,
[tex]y=\dfrac{3-3x}{2}[/tex]
Put this value in second equation of system A we get,
[tex]-2x-8\dfrac{3-3x}{2}=-1\\x=\dfrac{11}{10}[/tex]
Put this value in the first equation of system A, we get,
[tex]y=\dfrac{-3}{20}[/tex]
Similarly, on solving the system of equation B, we get the same value of variable x and y. Thus both the system has the same solution.
Therefore, they will have the same solution because the first equation of System B is obtained by adding the first equation of System A to 2 times the second equation of System A.
Learn more about the system of equations here;
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