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[tex]\bold{\huge{\underline{ Answers }}}[/tex]
Answer 1 :-
We know that,
- [tex]\bold{\pink{ 1 mol = 6.022 {\times} 10^{23}}}[/tex]
[ 6.022 × 10²³ is the Avogadro number ]
Therefore,
Number of atoms in 2.3 moles of Cu
[tex]\sf{ = 6.022 {\times} 10^{23}{\times}2.3 }[/tex]
[tex]\sf{ = 13.85 {\times} 10^{23} }[/tex]
[tex]\sf{ = 1.385 {\times} 10^{22} atoms }[/tex]
Hence, The number of atoms in 2.3 moles of Cu is 1.385 × 10²².
Answer 2 :-
We know that,
- [tex]\bold{\pink{ 1 mol = 6.022 {\times}10^{23}}}[/tex]
Therefore ,
Number of moles of water in 4.5 × 10²² molecules of water
[tex]\sf{ = }{\sf{\dfrac{4.5 {\times} 10^{22}}{6.022 {\times}10^{23}}}}[/tex]
[tex]\sf{ =}{\sf{ \dfrac{ 0.74}{10}}}[/tex]
[tex]\sf{ = 0.074 \:moles }[/tex]
Hence, The number of moles in 4.5 × 10²² molecules of water are 0.074 moles
Answer 3 :-
We know that,
- [tex]\bold{\pink{ 1 mol = 6.022 {\times}10^{23}}}[/tex]
Therefore ,
Number of moles in 2.4 × 10²³ molecules of water
[tex]\sf{ = }{\sf{\dfrac{2.4 {\times} 10^{23}}{6.022 {\times}10^{23}}}}[/tex]
[tex]\sf{ = 0.39 \:moles}[/tex]
Thus, The number of moles is 0.39
Now,
Number of atoms in 0.39 moles of CO
[tex]\sf{ = 6.022 {\times} 10^{23}{\times} 0.39 }[/tex]
[tex]\sf{ = 2.34 {\times} 10^{23} }[/tex]
[tex]\sf{ = 2.34 {\times} 10^{23} atoms }[/tex]
Hence, The number of atoms in 2.4 × 10²³ molecules of CO are 2.34 × 10²³
Answer 4 :-
We have ,
- 1.65 mol of barium phosphate
1 mol of Ba3(PO4)2 contains 8 moles of oxygen
Therefore ,
No. of oxygen moles in 1.65 mol of Ba3(PO4)2
[tex]\sf{ = 1.65 {\times} 8 }[/tex]
[tex]\sf{ = 13.2\: moles }[/tex]
Thus, 13.2 oxygen moles are present in 1.65 mol of Ba3(PO4)2
Now,
We have to calculate the number of oxygen atoms in 1.65 moles of Ba3(PO4)2
[tex]\sf{ = 6.022 {\times} 10^{23} {\times}13.2 }[/tex]
[tex]\sf{ = 79.79 {\times} 10^{22} }[/tex]
[tex]\sf{ = 7.979 {\times} 10^{22} atoms }[/tex]
Hence, The number of oxygen atoms in 1.65 moles of Ba3(PO4)2 are 7.979 × 10²²
Answer 5 :-
We know that,
- Atomic weight of gold = 197g(approx)
It means,
6.022 × 10²² = 197 g
Therefore,
No. of moles in 5.27g of gold
[tex]\sf{ = }{\sf{\dfrac{5.27 }{197}}}[/tex]
[tex]\sf{ = 0.026 \:moles }[/tex]
Now,
Atoms in 0.026 moles of gold
[tex]\sf{ = 6.022 {\times} 10^{23}{\times} 0.026 }[/tex]
[tex]\sf{ = 0.15 {\times} 10^{23 }[/tex]
[tex]\sf{ = 1.5 {\times} 10^{22} atoms }[/tex]
Hence, The number of atoms in 5.27g of golf are 1.5 × 10²²
Answer 6 :-
We have ,
- 1.95 × 10^25 atoms of boron
Therefore,
No. of moles of Boron
[tex]\sf{ = }{\sf{\dfrac{1.95 {\times}10^{25}}{6.022 {\times} 10^{23}}}}[/tex]
[tex]\sf{ = 0.32 {\times} 10^{2} }[/tex]
[tex]\sf{ = 32 \:moles }[/tex]
Thus, The number of moles is 32
Now,
We know that,
The atomic mass of boron = 11 u
Therefore,
The mass of 1.95 × 10^25 atoms of boron
[tex]\sf{ = 32 {\times} 11 }[/tex]
[tex]\sf{ = 352 g}[/tex]
Hence, The mass of 1.95 × 10^25 atoms of boron is 352 g.
[Note :- Kindly refer answer in app for better understanding ]
1. The number of atoms in 2.3 mole of Cu is 1.38×10²⁴ atoms
2. The number of mole of water in 4.5×10²² molecules is 0.075 mole
3. The number of atoms in 2.4×10²³ molecules of CO is 2.4×10²³ atoms
4. The number of oxygen atoms in 1.65 mol of barium phosphate is 4.82×10²⁴ atoms
5. The number of atoms in 5.72 g of gold is 1.75×10²² atoms
6. The mass of 1.95×10²⁵ atoms of boron is 356.31 g
Avogadro's hypothesis
1 mole of substance = 6.02×10²³ atoms
1. How to determine the number of atoms
1 mole of Cu = 6.02×10²³ atoms
Therefore,
2.3 moles of Cu = 2.3 × 6.02×10²³
2.3 moles of Cu = 1.38×10²⁴ atoms
2. How to determine the mole of water
6.02×10²³ molecules = 1 mole of water
Therefore,
4.5×10²² molecules = 4.5×10²² / 6.02×10²³
4.5×10²² molecules = 0.075 mole of water
3. How to determine the number of atoms
6.02×10²³ molecules = 1 mole of CO
Therefore,
2.4×10²³ molecules = 2.4×10²³ / 6.02×10²³
2.4×10²³ molecules = 0.4 mole of CO
But
1 mole of CO = 6.02×10²³ atoms
Thus,
0.4 mole of CO = 0.4 × 6.02×10²³
0.4 mole of CO = 2.4×10²³ atoms
Conclusion
2.4×10²³ molecules = 2.4×10²³ atoms of CO
4. How to determine the number of atoms
- Barium phosphate = Ba₃(PO₄)₂
- Mole of O in Ba₃(PO₄)₂ = 4 × 2 = 8 moles
- Atoms of O =?
1 mole of O = 6.02×10²³ atoms
Therefore,
8 moles of O = 8 × 6.02×10²³
8 moles of O = 4.82×10²⁴ atoms
5. How to determine the number of atoms
1 mole of gold = 6.02×10²³ atoms
But
1 mole of gold = 197 g
Thus, we can say that
197 g of gold = 6.02×10²³ atoms
Now, we can obtain the number of atoms in 5.72 g of gold as follow:
197 g of gold = 6.02×10²³ atoms
Therefore,
5.72 g of gold = (5.72 × 6.02×10²³) / 197
5.72 g of gold = 1.75×10²² atoms
6. How to determine the mass of boron
6.02×10²³ atoms = 1 mole of boron
But
1 mole of boron = 11 g
Thus, we can say that:
6.02×10²³ atoms = 11 g of boron
Now, we can determine the mass of boron which contains 1.95×10²⁵ atoms as follow:
6.02×10²³ atoms = 11 g of boron
Therefore,
1.95×10²⁵ atoms = (1.95×10²⁵ × 11) / 6.02×10²³
1.95×10²⁵ atoms = 356.31 g of boron
Learn more about Avogadro's number:
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