Respuesta :
Answer:
4 ohms
Explanation:
R = PL/A
P is resistivity
L is length and is halved
A cross sectional area, the same so
R = P(L/2)/A = 4
The resistance of the wire when the length is half will be 4 ohms. Resistance is directly propotional to the length in the given condition,
What is resistance?
Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.
The given data in the problem is;
The resistance in a piece of wire is R = 8 ohms.
D₁=D₂
T₁=T₂
L₂=0.5L₁
The formulas for the resistance in the wire will be;
[tex]\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{\rho L}{\frac{\pi}{4D^2} }[/tex]
If all the given values are constant the resistance is inversly propotional to the length.
If the length is half the value of the resistance is also half;
[tex]\rm R'=\frac{R}{2} \\\\ \rm R'=\frac{8}{2} \\\\ \rm R'=4 \ ohm[/tex]
Hence the resistance of the wire when the length is half will be 4 ohms.
To learn more about the resistance refer to the link;
https://brainly.com/question/20708652
