plss help me do this o-o
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Answer:
[tex]x=\sqrt6\\y=\sqrt{12}[/tex]
Step-by-step explanation:
We know that since angles in a triangle add up to 180º, the remaining angle must be 45º.
So the side with length [tex]x[/tex] must be equal to the side with length [tex]\sqrt6[/tex]. That is:
[tex]x=\sqrt6[/tex]
Now, by Pythagoras:
[tex]y=\sqrt{(\sqrt6)^2+(\sqrt6)^2}\\=\sqrt{6+6}\\=\sqrt{12}[/tex]
Answer:
[tex]x=\sqrt{6}[/tex]
[tex]y=2\sqrt{3}[/tex]
Step-by-step explanation:
Sum of the interior angles of a triangle = 180°
So the missing angle = 180 - 45 - 90 = 45°
Therefore, as two of the interior angles are congruent (both 45°), this is an isosceles triangle. This means that the two shorter sides are equal,
so [tex]x=\sqrt{6}[/tex]
Use Pythagoras' Theorem to calculate y:
[tex]y=\sqrt{(\sqrt{6})^2+(\sqrt{6})^2 } =\sqrt{12} =2\sqrt{3}[/tex]