Answer:
Step-by-step explanation:
If two chords intersect inside a circle, then
DE * BE =AE * CE
10*x = 8*6
10x = 48
x = 48/10
x = 4.8
[tex] \: \sf \: DE \times BE =AE \times CE \\ \\ \sf10 \times x = 8 \times 6 \\ \\ \sf10x = 48 \\ \\ \sf \: x = \dfrac{48}{10} \\ \\ \sf \: x = \cancel\dfrac{48}{10} \\ \\ \sf \red{x = 4.8}[/tex]
