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8. A ball is released from rest from the top of a cliff and accelerates downward. Approximately
how far does the ball travel in the first 5 seconds of its free-fall?

Respuesta :

cheemsburgerking
Take 10m/s^2 for the gravitational acceleration, as we know this is a free fall, we can use the equation: d=1/2*g*t^2

Substitute g=10m/s^2, t=5s, d=125m

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