As per questions,
2.
[tex] \frac{1}{9} \times \frac{3}{4} [/tex]
As 3 and 9 can be cancelled, we get,
[tex] \frac{1}{3} \times \frac{1}{4} [/tex]
Now multiplying denominators and numerators,
[tex] \frac{1}{12} [/tex]
Hence, the required answer is [tex] \frac{1}{12} [/tex]
4.
[tex] \frac{ \frac{5}{7} }{ \frac{2}{3} } [/tex]
When the base denominator (2/3) is reciprocaled,
[tex] \frac{5}{7} \times \frac{3}{2} [/tex]
As we can't directly divide, so we can multiply them,
[tex] \frac{5 \times 3}{7 \times 2} [/tex]
[tex]→ \frac{15}{14} [/tex]
Hence, the required answer is [tex] \frac{15}{14} [/tex]
5)
[tex]7.89 - 3.9[/tex]
Direct subtraction, (Check solution in attached image)
[tex]→3.99[/tex]
