Solve sin^2θ−4sinθ−5=0 for 0°≤θ≤360°
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Answer:
[tex]\theta=270^\circ[/tex]
Step-by-step explanation:
Given Equation and Parameters
[tex]sin^2\theta-4sin\theta-5=0,\: 0^\circ\leq\theta\leq 360^\circ[/tex]
Calculation
Let [tex]u=sin\theta[/tex], thus:
[tex]u^2-4u-5=0\\\\(u+1)(u-5)=0\\\\u=-1,\: u=5[/tex]
[tex]sin\theta=-1\\\\\theta=270^\circ[/tex]
[tex]sin\theta=5\\\\\theta=unde fined[/tex]
Conclusion
[tex]\theta=270^\circ[/tex]