Answer:
[tex]\frac{7}{3} =2\frac{1}{3}[/tex]
Step-by-step explanation:
For the problem:
[tex]\frac{5}{3} +\frac{4}{6} = ?[/tex]
The Least Common Multiple (LCM) of 3 and 6 is 6. Multiply the numerator and denominator of each fraction by whatever value will result in the denominator of each fraction being equal to the LCM:
[tex]\frac{5}{3} +\frac{4}{6} =\frac{5*2}{3*2} +\frac{4}{6} =\frac{10}{6} +\frac{4}{6}[/tex]
Now that the fractions have like denominators, add the numerators:
[tex]\frac{10}{6} +\frac{4}{6} =\frac{10+4}{6} =\frac{14}{6}[/tex]
The Greatest Common Factor (GCF) of 14 and 6 is 2. The result can be simplified by dividing both the numerator and denominator by 2.
[tex]\frac{14}{6} =\frac{14/2}{6/2} =\frac{7}{3}[/tex]
7 ÷ 3 = 2R1, therefore:
[tex]\frac{7}{3} =2\frac{1}{3}[/tex]
