Julia produces a 2 mA current by moving the south pole of a bar magnet into a solenoid. The solenoid contains 150 loops of wire. Which change should Julia make to generate a larger current? moving the magnet slower using more loops of wire in the coil using the north pole of the magnet setting the magnet down in the solenoid.

A solenoid is an electromagnet formed by a helical coil of wire. which generates a magnetic field when an electric current is passed through the coil.

According to Faraday's law of electromagnetic induction, the rate of change of magnetic flux linked with the coil is responsible for generating emf in the coil resulting in the vof the amount of current.

magnetic flux is defined as

Ф=NBA

[tex]EMF = \frac{d\phi}{dt} \\\\EMF = \frac{d(NBA)}{dt} \\\\[/tex]

[tex]EMF =NA \frac{d(B)}{dt} \\\\[/tex]

EMF is directly proportional to the amount of current. so that in order to increase the amount of current emf should be increasing and Emf is increased by the increasing no of the loop in the coil.

Hence Julia has to increase the no of loops in the coil in order to increase the generation of current.

To learn more about the solenoid refer to the link ;

https://brainly.com/question/16015159

Nabillassm Nabillassm · Answer 2 · 2022-05-24T20:30:54+02:00

Nabillassm Nabillassm

24-05-2022

Answer:

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Explanation:

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