A car is moving at 16 m/s at a time t = 0. With an acceleration of 0.50t, in m/s², for t, in seconds, it slows down. At t = 8 seconds, it stops. Option D is correct.
What is velocity?
The change of displacement with respect to time is defined as the velocity. velocity is a vector quantity.
Given data;
t = 0 ,u=16 m/s
acceleration = −0.50t m/s²
v=0,t=?
The acceleration is found as;
[tex]\rm a= \frac{dv}{dt} \\\\\ dv=adt \\\\ dv=-0.50 \ t dt[/tex]
Intregating both sides we get;
[tex]\rm [v]_0^{16}=-0.50\frac{t^2}{2} \\\\ 16=0.25 t^2\\\\\ t^2=\frac{16}{0.25} \\\\\ t= 8 \ sec[/tex]
Hence, the car stops at t=8sec. Option D is correct.
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