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*PLEASE I NEED HELP, WORTH 50 POINTS*

Cart A has mass M and is released from rest at a height 2H on a ramp making an angle 2 with the horizontal, as shown above. Cart B has mass 2M and is released from rest at a height H on a ramp making an angle with the horizontal. The carts roll toward each other, have a head- on collision on the horizontal portion of the ramp, and stick together. The masses of the carts’ wheels are negligible, as are any frictional or drag forces.


a.) Derive an expression to determine the velocity of Cart A in terms of the variables given in the prompt.


b.) Derive an expression to determine the velocity of Cart B in terms of the variables given in the prompt.


c.) Determine the final velocity of the carts after the collision.


d.) Is the collision elastic or inelastic? Justify your answer.


*Answers should only include variables.

PLEASE I NEED HELP WORTH 50 POINTSCart A has mass M and is released from rest at a height 2H on a ramp making an angle 2 with the horizontal as shown above Cart class=

Respuesta :

Based on the data provided;

  • the expression to determine the velocity of cart A is v = 2√gh
  • the expression to determine the velocity of cart B is v = 2√gh
  • the final velocity, v of the carts after the collision is v = {(1 - √2/)3} ×√gh
  • the collision is inelastic collisions because some energy of the entire system is lost when the carts stick together.

What are elastic and inelastic collisions?

Elastic collisions are collisions in which both energy and momentum is conserved.

Inelastic collisions are collisions in which only momentum is conserved but a decrease in the energy ofthe system occurs.

Applying the law of conservation of energy and the principle of conservation of momentum;

a. the kinetic energy, hence, the final velocity, v, of cart A is related to the change in gravitational potential energy

1/2mv^2 = mgh

v = 2√gh

b. the kinetic energy, hence, the final velocity, v, of cart B is related to the change in gravitational potential energy

1/2mv^2 = mgh

v = 2√gh

c. From the principle of conservation of linear momentum, momentum before and after collision is conserved.

Let the final velocity be v

3M × v = M × 2√gh - 2M × 2√gh

3v = 2(1 - √2) ×√gh

v = {(1 - √2/)3} ×√gh

d. Since the two cars stick together after collision, the collision is inelastic collision.

Learn more about elastic and inelastic collisions at: https://brainly.com/question/7694106