The balanced equation is:
4 NO(g) + O₂(g) ⇒ 2 N₂O₃(g)
The expression of the rate in terms of change in concentrations are:
[tex]v = \frac{-\Delta [NO]}{4\Delta t } = \frac{-\Delta [O_2]}{1\Delta t } = \frac{\Delta [N_2O_3]}{2\Delta t }[/tex]
When N₂O₃ is forming at 0.221 M/s, NO is disappearing at 0.442 M/s.
The reaction rate is the speed at which a chemical reaction takes place, defined as proportional to the increase in the concentration of a product per unit time and to the decrease in the concentration of a reactant per unit time.
4 NO(g) + O₂(g) ⇒ 2 N₂O₃(g)
We will need to consider the stoichiometric coefficient of each species.
[tex]v = \frac{-\Delta [NO]}{4\Delta t } = \frac{-\Delta [O_2]}{1\Delta t } = \frac{\Delta [N_2O_3]}{2\Delta t }[/tex]
The molar ratio of NO to N₂O₃ is 4:2.
[tex]\frac{0.221molN_2O3}{L.s} \times \frac{4molNO}{2molN_2O_3} = \frac{0.442 molNO}{L.s}[/tex]
The balanced equation is:
4 NO(g) + O₂(g) ⇒ 2 N₂O₃(g)
The expression of the rate in terms of change in concentrations are:
[tex]v = \frac{-\Delta [NO]}{4\Delta t } = \frac{-\Delta [O_2]}{1\Delta t } = \frac{\Delta [N_2O_3]}{2\Delta t }[/tex]
When N₂O₃ is forming at 0.221 M/s, NO is disappearing at 0.442 M/s.
Learn more about reaction rate here: https://brainly.com/question/1898560
