contestada

In the following balanced neutralization reaction equation, how many moles of Ca(OH)2 are required to completely neutralize 1.2 moles of HI? 2HI + Ca(OH)2 → CaI2 + 2H2O

Respuesta :

0.6 moles is the answer

Answer : The number of moles of [tex]Ca(OH)_2[/tex] required are, 0.6 mole.

Explanation : Given,

Moles of HI = 1.2 moles

The given balanced chemical reaction is,

[tex]2HI+Ca(OH)_2\rightarrow CaI_2+2H_2O[/tex]

From the balanced chemical reaction, we conclude that

As, 2 moles of [tex]HI[/tex] react with 1 mole of [tex]Ca(OH)_2[/tex]

So, 1.2 moles of [tex]HI[/tex] react with [tex]\frac{1.2}{2}=0.6[/tex] mole of [tex]Ca(OH)_2[/tex]

Therefore, the number of moles of [tex]Ca(OH)_2[/tex] required are, 0.6 mole.