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A woman stands at a horizontal distance x from a mountain and measures the angle of elevation of the mountaintop above the horizontal as θ. After walking a distance d closer to the mountain on level ground, she finds the angle to be ϕ. Find a general equation for the height y of the mountain in terms of d, ϕ, and θ, neglecting the height of her eyes above the ground.

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Answer:[tex]y=\frac{d\times tan\phi\times tan\theta}{tan\phi-tan\theta}[/tex]

Explanation;

In ABC=

[tex]Tan\theta=\frac{y}{x}[/tex]

[tex]x=\frac{y}{tan\theta}[/tex]

In ADC

[tex]Tan\phi=\frac{y}{x-d}[/tex]

Using value of x from (1) in (2) , we get:

[tex]y=\frac{d\times tan\phi\times tan\theta}{tan\phi-tan\theta}[/tex]

General equation for the height y of the mountain in terms of d, ϕ, and θ.

[tex]y=\frac{d\times tan\phi\times tan\theta}{tan\phi-tan\theta}[/tex]

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