Answer:
Step-by-step explanation:
ΔADB is a right angled triangle. So, use Pythagorean theorem.
Altitude² = hypotenuse² - base²
= (2√5)² - (3√2)²
= 2²* (√5)² - 3²*(√2)² = 4*5 - 9*2 = 20 - 18 = 2
Altitude = √2
Base of ΔABC = 3√2 + √2 = 4√2 cm
Area = [tex]\dfrac{1}{2}bh[/tex]
[tex]= \dfrac{1}{2}*4\sqrt{2}*\sqrt{2}\\\\\\=\dfrac{1}{2}*4*\sqrt{2*2}\\\\\\=\dfrac{1}{2}*4*2\\\\= 4 cm^{2}[/tex]
