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Question: What is the value of X°
In this complementary angle? ​

PLS HELPI need help on this and please provide an explanationThank you Question What is the value of X In this complementary angle class=

Respuesta :

Answer:

x=30

Yes, they are complementary

Step-by-step explanation:

The two angles shown add up to the right angle marked. Right angles are 90 degrees. Set up the following equation:

2x°+x°=90

3x°=90

x=30

Complementary angles are two angles that add up to 90°. Since the two angles add up to 90 degrees, they are complementary.

Answer:

[tex]\boxed{\boxed{ \tt \: x = 30 {}^{ \circ}}} [/tex]

Step-by-step explanation:

The Given two angles are complementary angles .

The Two angles are 2x° and x°.[Given]

[Two angles are called complementary if their sum is 90°. Each angle is a complement to each other.]

We need to find the value of x.

So,

[tex] \tt2x {}^{ \circ} + {x}^{ \circ} = 90{}^{ \circ} [/tex]

Solve this equation.

[tex]\tt \implies(2x + {x} ){}^{ \circ} = 90{}^{ \circ} [/tex]

Combine the like terms:

[tex]\tt3x{}^{ \circ} = 90{}^{ \circ} [/tex]

Divide both sides by 3 :

[tex] \tt \implies \cfrac{3x{}^{ \circ} }{3{}^{ \circ} } = \cfrac{90{}^{ \circ} }{3{}^{ \circ} } [/tex]

Cancel the LHS and RHS:

[tex] \tt \implies \cfrac{ \cancel{3x{}^{ \circ}} }{ \cancel{3{}^{ \circ}} } = \cfrac{ \cancel{90}{}^{ \circ} }{ \cancel{3{}^{ \circ}} } [/tex]

[tex] \tt \implies \cfrac{1x{}^{ \circ} }{1{}^{ \circ} } = \cfrac{30{}^{ \circ} }{1{}^{ \circ} } [/tex]

[tex] \tt \implies 1x{}^{ \circ} = 30{}^{ \circ} [/tex]

[tex] \tt \implies x{}^{ \circ} = 30{}^{ \circ} [/tex]

[tex] \tt \implies x{}^{ \circ} = 30{}^{ \circ} [/tex]

Hence, the value of x° would be 30°.

[tex] \rule{225pt}{2pt}[/tex]

I hope this helps!