mariaguadaluperdgz97
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when three squares are joined at their vertices to form a right triangle, the combined are of the two smaller squares is the same of the area of largest square. Which three squares do NOT support this statement ?​

when three squares are joined at their vertices to form a right triangle the combined are of the two smaller squares is the same of the area of largest square W class=

Respuesta :

Ancillary

Answer:

C. 9, 40, 42

Step-by-step explanation:

C is the only set of three values that is not a Pythagorean Triple. In other words, they do not satisfy [tex]a^2+b^2=c^2[/tex], as stipulated in the problem.

⇒ Answer choice C

himaruanuk

Answer:

C

Step-by-step explanation:

Use phytogoras theorem

First small square area + second small square area = large square area

9 * 9 + 40 *40

81+ 1600= 1681(large square area)

Large square length =

Square root of 1681 = 41

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