Gravitational potential energy (Eg) and kinetic energy (Ek)

A 70.0 kg athlete is running at a 12m/s in the 100.0m dash. What is the kinetic energy of the athlete?​

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Answer:

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Explanation:

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Answer:

[tex]\boxed {\boxed {\sf E_K= \ 5,040 \ J}}[/tex]

Explanation:

Kinetic energy is the energy an object possesses due to motion. It is calculated using the following formula:

[tex]E_K= \frac{1}{2} mv^2[/tex]

The mass of the athlete is 70.0 kilograms. The velocity is 12 meters per second.

  • m= 70.0 kg
  • v= 12 m/s

Substitute the values into the formula.

[tex]E_K= \frac{1}{2} (70.0 \ kg)(12 \ m/s)^2[/tex]

Solve the exponent.

  • (12 m/s)² = (12 m/s)(12 m/s) = 144 m²/s²

[tex]E_K= \frac{1}{2} (70.0 \ kg)(144 \ m^2/s^2)[/tex]

Multiply the numbers together.

[tex]E_K= \frac{1}{2} (10, 080 \ kg*m^2/s^2)[/tex]

[tex]E_K= 5,040 \ kg*m^2/s^2[/tex]

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer is equal to 5,040 Joules.

[tex]E_K= 5.040 \ J[/tex]

The athlete has 5,040 Joules of kinetic energy.