A radioactive substance loses its mass at a rate of 12% every second. At the beginning of an experiment, the substance has a mass of 6 cg.

Which of the following equations best models the exponential function of this situation?

f(t) =6(0.88)(t)

f(t) =0.88(6)(t)

f(t) =0.88(t)(6)

f(t) =0.12(6)(t)

f(t) =6(0.12)(t)

Respuesta :

Answer:  [tex]\boldsymbol{f(t) = 6(0.88)^t}[/tex] which is choice A

This is the same as writing f(t) = 6(0.88)^t

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Explanation:

Exponential equations can be written in the form [tex]y = a*b^x[/tex]

The 'a' represents the starting amount which means a = 6.

The b value is tied to the growth or decay.

In this case, we have r = -0.12 representing a decay of 12%

So b = 1+r = 1 + (-0.12) = 0.88

Therefore, we go from [tex]y = a*b^x[/tex] to [tex]y = 6(0.88)^x[/tex]

Then replace x with t, and replace y with f(t) to end up with [tex]f(t) = 6(0.88)^t[/tex]

Note: the 0.88 represents having 88% leftover when you lose 12% of the mass.

Answer: f(t)=6(0.88)^t

Step-by-step explanation:

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