With an explanation please!

A car of mass 500kg is moving at 10m/s. The engine does work on the car and the speed increases to 16m/s. How much work is done by the engine to increase the speed of the car?

Respuesta :

Answer:

39,000 Joules of Work

Explanation:

Work can be found out through the change in Kinetic Energy.

W = ΔKE

Change in KE is:

[tex]W = KE_{Final} - KE_{Initial}[/tex]

Expand the equation you get:

[tex]W=\frac{1}{2} mv^{2}_{f} -\frac{1}{2} mv^{2}_{i}[/tex]

Plugin the known values and solve:

[tex]W=\frac{1}{2} (500)(16)^{2} -\frac{1}{2} (500)(10)^{2}[/tex]

[tex]W=(250)(256) -(250)(100)[/tex]

[tex]W=64000-25000[/tex]

[tex]W=39000 J[/tex]