Please help!!!!!!!!!!!!!!!!
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Answer:
(i) x° = 28°
(ii) y° = 104°
(iii) z° = 76°
Step-by-step explanation:
x° is an alternate interior angle where transversal PQ crosses the parallel lines, so it has the same measure as the one marked 28°.
x° = 28°
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The base angles of isosceles triangle PQR are both z°, so we must have ...
z° +z° +28° = 180° . . . . . . . . . sum of angles in a triangle
z° = (180° -28°)/2 = 152°/2 . . . solve for z
z° = 76°
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y° and z° are a linear pair, so ...
y° = 180° -76°
y° = 104°