The acceleration of the block is 15.97 m/s².
Acceleration of the block
The acceleration of the box is determined by taking the net force on the block as follows;
∑F = ma
[tex]Fcos(\theta) = ma\\\\a = \frac{Fcos(\theta}{m}[/tex]
where;
- F is horizontal force
- M is the mass of the block
- a is the acceleration
The acceleration of the block is calculated as follows;
[tex]a = \frac{200 \times cos(37)}{10} \\\\a = 15.97 \ m/s^2[/tex]
Learn more about acceleration here: https://brainly.com/question/22048837
