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The percent by mass of Lead in Lead (IV) oxide ([tex]PbO_2[/tex]) is equal to 86.62%.

Scientific data:

  • Molar mass of Lead = 207.2 g/mol.
  • Molar mass of oxygen = 16 g/mol.

To calculate the percent by mass of Lead in Lead (IV) oxide ([tex]PbO_2[/tex]):

First of all, we would calculate the molar mass of Lead (IV) oxide ([tex]PbO_2[/tex]);

[tex]PbO_2 = 207.2 + 16(2)\\ \\ [/tex]

Lead (IV) oxide ([tex]PbO_2[/tex]) = 239.2 g/mol.

How to calculate percent by mass.

For the percent by mass of Lead, we would calculate it by using this formula:

[tex]P = \frac{Mass}{Mass\;of\;compound} \times 100[/tex]

Substituting the parameters into the formula, we have;

[tex]P = \frac{207.2}{239.2} \times 100\\ \\ P=0.8662 \times 100[/tex]

Percent mass of Lead = 86.62%

Read more on percent mass here: https://brainly.com/question/15182450

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