A grocer sold 25 fewer kilograms of fruit on the first day of operation
than he did on the second day. On the third day, the grocer sold 27of
the fruit he had sold on the first and second days combined. How many
kilograms of fruit did the grocer sell each day if he sold 315 kg in total?
PLEASE HURRY

Respuesta :

The number of fruits sold on the first day is 18.125 kg

How to find total fruits sold

Let

  • Number of fruits sold on the second day = x

  • Number of fruits sold on the first day = x - 25

  • Number of fruits sold on the third day = 27 × {x + (x - 25)}

= 27 × ( x + x - 25)

= 27 × (2x - 25)

= 54x - 675

  • Total fruits sold = 315

315 = x + (x - 25) + (54x-675)

315 = x + x - 25 + 54x - 675

315 = 56x - 700

315 + 700 = 56x

1015 = 56x

x = 1015 / 56

= 18.125 kg

Number of fruits sold on the second day = x

= 18.125kg

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The amount in kilogram of fruit the grocer sold each day is as follows:

First day sales(kg) = 110 kg

Second day sales(kg) = 135 kg

Third day sales(kg)  = 70 kg

Ratios and proportions

Let

the amount he sold on the second day = x

He sold 25 fewer kilograms of fruit on the first day of operation than he did on the second day. Therefore, the first day sales will be as follows;

  • x - 25

On the third day, the grocer sold 2 / 7 of the fruit he had sold on the first and second days combined. Therefore, the third day sales will be as follows:

  • 2 / 7 (2x - 25)

If he sold 315 kg in total the amount he sold each day can be calculated as follows:

  • x + x -25 + 2 / 7(2x -25) = 315

2x - 25 + 4x / 7 - 50 / 7 = 315

2x + 4x / 7 = 315 + 25 + 50 / 7

14x + 4x / 7 = 340 + 50 / 7

18x / 7 = 2380 + 50 / 7

18x / 7 = 2430 / 7

18x = 2430

x = 2430 / 18

x = 135

Therefore,

First day sales(kg) = 135 - 25 = 110 kg

Second day sales(kg) = 135 kg

Third day sales(kg) = 315 - 135 - 110 = 70 kg

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