A bag contains 6 red, 5 blue, and 4 yellow marbles. Two marbles are drawn from the bag, but the first marble drawn is not replaced. What is the probability of selecting a red marble, and then a blue marble?

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jtm2588 jtm2588 · Answer 1 · 2022-01-15T02:54:58+01:00

Answer:

(p red) = 2/5

(p blue) = 5/14

Step-by-step explanation:

add to number of marbles to get how many are in the bag.

6 + 5 + 4 = 15

Find the probability of drawing a red marble.

(p red) = 6/15

reduce by 3

(p red) = 2/5

The marble isn't replaced, so now there are 14 marbles in the bag. Find the probability of drawing a blue marble.

(p blue) = 5/14

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ap8997154 ap8997154 · Answer 2 · 2022-05-26T11:19:15+02:00

The probability of selecting a red marble without replacing it, and then a blue marble is 0.1428.

Probability helps us to know the chances of an event occurring.

Probability=Desired Outcome/Total Number of outcomes possible

The probability of selecting a red marble without replacing it, and then a blue marble will be,

[tex]{\rm Probability} = \dfrac{6}{15} \times \dfrac{5}{14} = \dfrac{30}{210} = 0.1428[/tex]

Hence, the probability of selecting a red marble without replacing it, and then a blue marble is 0.1428.

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