Find the position and velocity of a particle at T=2.00s if the particle is initially moving east at a speed of 20.0m/s and experiences an acceleration of magnitude 4.00 m/s^2, directed west
Please help and prove your answer with steps
Thx in advance
assuming they start at 0,0, with east being the positive direction, and west negative use the equation d=vit + (at^2)/2 vi = initial velocity = 20.0m/s, t= 2.00s, a= -4.00m/s^2 d = 20(2) + (-4(2^2))/2 d = 40 - 8 d = 32m east
