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What are the lengths of the other two sides of the triangle? AC = 5 and BC = 5 AC = 5 and BC = 5 StartRoot 5 EndRoot AC = 5 StartRoot 3 EndRoot and BC = 5 AC = 5 and BC = 5 StartRoot 3 EndRoot.

Respuesta :

The given triangle is a right triangle. You can use trigonometric ratios to find the remaining sides of the triangle.

The remaining two sides of the given triangle are of given below measures:

|AC| = 5 units

|BC| = [tex]5\sqrt3[/tex] units.

Given that:

  • The side AB = hypotenuse = 10 units.
  • Angle C is of 90 degrees measure.
  • Angle B is of 30 degrees measure.

To find:

Lengths of remaining sides

Using sine and cosine trigonometric ratio using angle B, we get:

[tex]sin(30^\circ) = \dfrac{|AC|}{|AB|}\\\\\dfrac{1}{2} = \dfrac{|AC|}{10}\\\\|AC| = \dfrac{10}{2} = 5 \: \rm units[/tex]

Similarly, we get:

[tex]cos(30^\circ) = \dfrac{|BC|}{|AB|}\\\\\dfrac{\sqrt3}{2} = \dfrac{|BC|}{10}\\\\|BC| = \dfrac{10 \sqrt3}{2} = 5\sqrt3 \: \rm units[/tex]

Thus, the remaining two sides of the given triangle are of given below measures:

|AC| = 5 units

|BC| = [tex]5\sqrt3[/tex] units.

Learn more about trigonometric ratios here:

https://brainly.com/question/13571619

Ver imagen astha8579

Ok so basically the answer is DDD on edge,

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