The integers in the interval −3 ≤ x ≤ 4 that satisfy the inequality 3x + 9 ≥ 3 are -2, -1, 0, 1, 2, 3, 4.
To find the values of x in the interval −3≤x≤4 that satisfy the following inequality: 3x + 9 ≥ 3, we solve the inequality.
So, 3x + 9 ≥ 3
Subtracting 9 from both sides, we have
3x + 9 - 9 ≥ 3 - 9
3x + 0 ≥ -6
3x ≥ -6
Dividing both sides by 3, we have
3x/3 ≥ -6/3
x ≥ -2
So, for the interval −3≤x≤4 the values of x that satisfify the inequality must be in the interval x ≥ - 2 and x ≤ 4 ⇒ -2 ≤ x ≤ 4.
So, the integers in this interval are -2, -1, 0, 1, 2, 3, 4.
So, the integers in the interval −3 ≤ x ≤ 4 that satisfy the inequality 3x + 9 ≥ 3 are -2, -1, 0, 1, 2, 3, 4.
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