For an experiment, a scientist designs a can, 20 cm in height, that can hold water. A
tube is installed at the bottom of the can allowing water to drain out.
At the beginning of the experiment, the can is full. When the experiment starts, the
water begins to drain, and the height of the water in the can decreases by a factor of.
!
each minute.
a. Explain why the height of the water in the can is a function of time.
b. The height, h, in cm, is a function / of time t in minutes since the beginning of the
experiment, h = f(t). Find an expression for f(t).
c. Find and record the values for / when t is 0, 1, 2, and 3.
d. Find f(4). What does f (4) represent?

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rvaasunthra rvaasunthra · Answer 1 · 2022-01-18T05:15:36+01:00

Step-by-step explanation:

The height of the water in the can is a function of time, because it depends on the time the water flows out each minute.

The height h in cm is a function f of time t in minutes since poking the hole, h= f(t)h=f(t). The expression for f(t) = 20. \frac{2}{3}^{t}f(t)=20.

3

2

t

The values of f -> f(0) = 20f(0)=20; f(1) = \frac{40}{3}f(1)=

3

40

; f(2) = \frac{80}{9}f(2)=

9

80

; f(3) = \frac{160}{27}f(3)=

27

160

The value of f(5) = \frac{640}{243}f(5)=

243

640

The level of water approaches close to the x-axis as time moves on. It does not completely approach zero.

Sorry if wrong answer