contestada

Triangle ABC is an isosceles with AC=CB=8cm CD is an arc of a circle centre B and angle ABC=0.9radians. Find
I) the length of CD
ii) the length of AD
iii) the perimeter of the shaded portion

Triangle ABC is an isosceles with ACCB8cm CD is an arc of a circle centre B and angle ABC09radians Find I the length of CD ii the length of AD iii the perimeter class=

Respuesta :

adioabiola
  • The Length of CD is; 7.21cm
  • The length of AC is; 4.96cm
  • The perimeter of the shaded portion is; 20.17cm

How to find perimeter of a triangle

From isosceles triangles; we can establish that the

Angles CAD = CBD.

Hence, angle CAD = 0.9radians = 51.57°

  • The length of the arc CD is;

L = (51.67/360) × 2 × 3.14 × 8

L = 7.21cm = CD.

  • To find the length of AC; From trigonometric identities; Cos 51.67 = AD/8cm

AD = 0.62 × 8

AD = 4.96cm

  • The perimeter of the shaded portion is therefore; 7.21 + 4.96 + 8 = 20.17cm

Learn more on length of an arc:

https://brainly.com/question/2005046

Otras preguntas