35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.
Equation of the reaction
The equation of the reaction is given below:
PCl₅ + H2O ---> POCl₃ + 2 HCl
How to calculate grams of PCl₅ required to produce 12.6 g of HCl
Molar mass of PCl₅ = 208.5 g
Molar mass of Hcl = 36.5 g
Moles of HCl = mass / molar mass
Moles of HCl = 12.6 / 36.5
moles of HCl = 0.345 moles
2 moles of HCl are produced by 1 mole of PCl₅
0.345 moles of HCl will be produced by 0.345/2 = 0.1725 moles of PCl₅
Mass of 0.1725 moles of PCl₅ = 0.1725 * 208.5 = 35.9 g of PCl₅
Mass of PCl₅ = 35.9 g of PCl₅
Therefore, 35.9 g of PCl₅ will be required to produce produce 12.6 g of HCl.
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