Answer:
A concentrated solution has a greater amount of dissolved solute than a dilute solution. Explanatio ... More
1.2 liters of a 0.35 M solution of sodium chloride could be formed with 25 grams of NaCl.
Molarity (M) is defined as the number of solute dissolved in per liter of solution.
Molarity (M) = [tex]\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liter)}}[/tex]
M = [tex]\frac{n}{V}[/tex]
where
M is molarity, n is number of moles and V is volume of solution.
First we have to find the number of moles
Number of moles (n) = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]
Molar mass of NaCl = 23 g/mol + 35.5 g/mol = 58.5 g/mol
Now,
Number of moles (n) = [tex]\frac{\text{Given Mass}}{\text{Molar mass}}[/tex]
= [tex]\frac{25 g}{58.5 g/mol}[/tex]
= 0.427
Now, we have to find the volume of solution
M = [tex]\frac{n}{V}[/tex]
0.35 = [tex]\frac{0.427}{V}[/tex]
V = [tex]\frac{0.427}{0.35}[/tex]
V = 1.2 liter
Thus, 1.2 liter of 0.35M solution of sodium chloride could be formed with 25 grams of NaCl.
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