The amount of charge on each plate is equal to 0.9 Coulombs.
Given the following data:
To calculate the amount of charge on each plate:
Mathematically, work done in moving a charge is given by this formula:
[tex]W=qV[/tex]
Note: The work done by an external force equals the change in potential energy for the charges that were moved.
[tex]W= \Delta P.E = qV[/tex]
But, [tex]V=\frac{Q}{C}[/tex]
Now, the work done becomes:
[tex]W=q\frac{Q}{C}[/tex]
Making q the subject of formula, we have:
[tex]q=\frac{WC}{Q} \\\\q=\frac{18 \times 15 \times 10^{-6}}{0.3 \times 10^{-3}}[/tex]
Charge, q = 0.9 Coulombs.
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