Answer: Choice B
12.5 < x < 18.9
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Explanation:
We have a triangle with these side lengths:
- a = 10
- b = 16
- c = x = unknown
Let's assume that b = 16 is the largest side of this triangle.
By the converse of the pythagorean theorem, we need [tex]b^2 < a^2+c^2[/tex] to be true in order for an acute triangle to happen.
So,
[tex]b^2 < a^2 + c^2\\\\c^2 > b^2 - a^2\\\\c > \sqrt{b^2-a^2}\\\\x > \sqrt{16^2-10^2}\\\\x > \sqrt{156}\\\\x > 12.4899959967968 \ \text{(approximate)}\\\\x > 12.5[/tex]
Now let's consider the possibility that the missing side x is actually the longest side.
Using the same theorem as before, we would say,
[tex]c^2 < a^2 + b^2\\\\c < \sqrt{a^2 + b^2}\\\\x < \sqrt{10^2 + 16^2}\\\\x < \sqrt{356}\\\\x < 18.8679622641132 \ \text{(approximate)}\\\\x < 18.9\\\\[/tex]
We found that x > 12.5 and x < 18.9
This is the same as saying 12.5 < x and x < 18.9
Put together, they form the approximate answer of 12.5 < x < 18.9
