Given that N is the incenter of △ABC, NS = 4.
Given the image where:
NQ = 2x
NR = 3x − 2
NQ = NR = NS (equidistant from the incenter)
Thus:
2x = 3x - 2
2x - 3x = -2
-x = -2
x = 2
NQ = NS = 2x
NS = 2(2)
NS = 4
Therefore, given that N is the incenter of △ABC, NS = 4.
Learn more about the incenter on:
https://brainly.com/question/1831482