In the circle, AB= 34, BC = 12 and CD= 8

Answer:
Option A. x = 61
Step-by-step explanation:
If two secants are intersecting each other on a point outside the circle then by theorem of intersecting secants
(x + CD)×CD = AC×BC
(x + CD)×CD = (AB + BC) × BC
Here AB = 34, BC = 12, and CD = 8
(x + 8) × 8 = (34 + 12) × 12
8x + 64 = 46×12 = 552
8x = 552 - 64 = 488
x = 488 ÷ 8
x = 61
Therefore option A. x = 61 will be the answer.