Using the given discrete distribution, it is found that the standard deviation is of 1.251 shows.
What are the mean and the standard deviation of a discrete distribution?
- The mean is given by the sum of the multiplications of each outcome by it's probability, thus:
- The standard deviation is given by the square root of the sum of the squares of each outcome subtracted by the mean, multiplied by it's probability, thus:
The distribution is:
[tex]P(X = 0) = 0.095[/tex]
[tex]P(X = 1) = 0.203[/tex]
[tex]P(X = 2) = 0.326[/tex]
[tex]P(X = 3) = 0.187[/tex]
[tex]P(X = 4) = 0.174[/tex]
[tex]P(X = 5) = 0.015[/tex]
Hence, the mean is:
[tex]E(X) = 0.095(0) + 0.203(1) + 0.326(2) + 0.187(3) + 0.174(4) + 0.015(5) = 2.187[/tex]
The standard deviation is:
[tex]\sqrt{V(X)} = \sqrt{0.095(0-2.187)^2+0.203(1-2.187)^2+0.326(2-2.187)^2+0.187(3-2.187)^2+0.174(4-2.187)^2+0.015(5-2.187)^2} = 1.251[/tex]
You can learn more about the mean and the standard deviation of a discrete distribution at https://brainly.com/question/13008984