The number of molecules in 1 drop of the water is 1.67×10²¹ molecules
We'll begin by calculating the mass of the water. This can be obtained as follow:
•Volume = 50 μL = 50×10¯⁶ L = 50×10¯⁶ × 10³ = 0.05 mL
•Density = 1 g/mL
•Mass =?
Mass = Density × Volume
Mass of water = 1 × 0.05
Mass of water = 0.05 g
1 mole of water = 6.02×10²³ molecules
1 mole of water = 18 g
Thus,
18 g of water = 6.02×10²³ molecules
Therefore,
0.05 g of water = (0.05 × 6.02×10²³) / 18
0.05 g of water = 1.67×10²¹ molecules
Thus, the number of molecules in 1 drop of the water is 1.67×10²¹ molecules
Learn more about Avogadro's number:
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