Please help me solve this question
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Answer:
sin(0) = opposite/hypotenuse = (3√3)/√31
cos(0) = adjacent/hypotenuse = 2/√31
tan(0) = opposite/adjacent = (3√3)/2
cot(0) = 2/(3√3)
sec(0) = 1/cos(0) = 1/(2/√31) = √31/2
Step-by-step explanation:
Hypertenuse = √[2^2 + (3√3)^2] = √[4 + 27] = √31
sin(0) = opposite/hypotenuse = (3√3)/√31
cos(0) = adjacent/hypotenuse = 2/√31
tan(0) = opposite/adjacent = (3√3)/2
cot(0) = 2/(3√3)
sec(0) = 1/cos(0) = 1/(2/√31) = √31/2
I hope this helps